Optimal. Leaf size=106 \[ \frac{2 i c^{3/2} \tan ^{-1}\left (\frac{\sqrt{c} \sqrt{a+i a \tan (e+f x)}}{\sqrt{a} \sqrt{c-i c \tan (e+f x)}}\right )}{\sqrt{a} f}+\frac{2 i c \sqrt{c-i c \tan (e+f x)}}{f \sqrt{a+i a \tan (e+f x)}} \]
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Rubi [A] time = 0.142339, antiderivative size = 106, normalized size of antiderivative = 1., number of steps used = 5, number of rules used = 5, integrand size = 35, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.143, Rules used = {3523, 47, 63, 217, 203} \[ \frac{2 i c^{3/2} \tan ^{-1}\left (\frac{\sqrt{c} \sqrt{a+i a \tan (e+f x)}}{\sqrt{a} \sqrt{c-i c \tan (e+f x)}}\right )}{\sqrt{a} f}+\frac{2 i c \sqrt{c-i c \tan (e+f x)}}{f \sqrt{a+i a \tan (e+f x)}} \]
Antiderivative was successfully verified.
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Rule 3523
Rule 47
Rule 63
Rule 217
Rule 203
Rubi steps
\begin{align*} \int \frac{(c-i c \tan (e+f x))^{3/2}}{\sqrt{a+i a \tan (e+f x)}} \, dx &=\frac{(a c) \operatorname{Subst}\left (\int \frac{\sqrt{c-i c x}}{(a+i a x)^{3/2}} \, dx,x,\tan (e+f x)\right )}{f}\\ &=\frac{2 i c \sqrt{c-i c \tan (e+f x)}}{f \sqrt{a+i a \tan (e+f x)}}-\frac{c^2 \operatorname{Subst}\left (\int \frac{1}{\sqrt{a+i a x} \sqrt{c-i c x}} \, dx,x,\tan (e+f x)\right )}{f}\\ &=\frac{2 i c \sqrt{c-i c \tan (e+f x)}}{f \sqrt{a+i a \tan (e+f x)}}+\frac{\left (2 i c^2\right ) \operatorname{Subst}\left (\int \frac{1}{\sqrt{2 c-\frac{c x^2}{a}}} \, dx,x,\sqrt{a+i a \tan (e+f x)}\right )}{a f}\\ &=\frac{2 i c \sqrt{c-i c \tan (e+f x)}}{f \sqrt{a+i a \tan (e+f x)}}+\frac{\left (2 i c^2\right ) \operatorname{Subst}\left (\int \frac{1}{1+\frac{c x^2}{a}} \, dx,x,\frac{\sqrt{a+i a \tan (e+f x)}}{\sqrt{c-i c \tan (e+f x)}}\right )}{a f}\\ &=\frac{2 i c^{3/2} \tan ^{-1}\left (\frac{\sqrt{c} \sqrt{a+i a \tan (e+f x)}}{\sqrt{a} \sqrt{c-i c \tan (e+f x)}}\right )}{\sqrt{a} f}+\frac{2 i c \sqrt{c-i c \tan (e+f x)}}{f \sqrt{a+i a \tan (e+f x)}}\\ \end{align*}
Mathematica [A] time = 2.71588, size = 119, normalized size = 1.12 \[ \frac{c^2 (\cos (f x)+i \sin (f x)) (\sin (f x)+i \cos (f x)) \left (-i \tan (e+f x)+\sec (e+f x) \tan ^{-1}(\cos (e+f x)+i \sin (e+f x))+1\right )}{f \sqrt{a+i a \tan (e+f x)} \sqrt{\frac{c}{2 i \sin (2 (e+f x))+2 \cos (2 (e+f x))+2}}} \]
Antiderivative was successfully verified.
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Maple [B] time = 0.082, size = 269, normalized size = 2.5 \begin{align*}{\frac{ic}{fa \left ( -\tan \left ( fx+e \right ) +i \right ) ^{2}}\sqrt{-c \left ( -1+i\tan \left ( fx+e \right ) \right ) }\sqrt{a \left ( 1+i\tan \left ( fx+e \right ) \right ) } \left ( i\ln \left ({ \left ( ac\tan \left ( fx+e \right ) +\sqrt{ac \left ( 1+ \left ( \tan \left ( fx+e \right ) \right ) ^{2} \right ) }\sqrt{ac} \right ){\frac{1}{\sqrt{ac}}}} \right ) \left ( \tan \left ( fx+e \right ) \right ) ^{2}ac-i\ln \left ({ \left ( ac\tan \left ( fx+e \right ) +\sqrt{ac \left ( 1+ \left ( \tan \left ( fx+e \right ) \right ) ^{2} \right ) }\sqrt{ac} \right ){\frac{1}{\sqrt{ac}}}} \right ) ac-2\,i\sqrt{ac}\sqrt{ac \left ( 1+ \left ( \tan \left ( fx+e \right ) \right ) ^{2} \right ) }\tan \left ( fx+e \right ) +2\,\ln \left ({\frac{ac\tan \left ( fx+e \right ) +\sqrt{ac \left ( 1+ \left ( \tan \left ( fx+e \right ) \right ) ^{2} \right ) }\sqrt{ac}}{\sqrt{ac}}} \right ) \tan \left ( fx+e \right ) ac-2\,\sqrt{ac \left ( 1+ \left ( \tan \left ( fx+e \right ) \right ) ^{2} \right ) }\sqrt{ac} \right ){\frac{1}{\sqrt{ac \left ( 1+ \left ( \tan \left ( fx+e \right ) \right ) ^{2} \right ) }}}{\frac{1}{\sqrt{ac}}}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [A] time = 1.97064, size = 171, normalized size = 1.61 \begin{align*} -\frac{{\left (2 i \, c \arctan \left (\cos \left (f x + e\right ), \sin \left (f x + e\right ) + 1\right ) + 2 i \, c \arctan \left (\cos \left (f x + e\right ), -\sin \left (f x + e\right ) + 1\right ) - 4 i \, c \cos \left (f x + e\right ) + c \log \left (\cos \left (f x + e\right )^{2} + \sin \left (f x + e\right )^{2} + 2 \, \sin \left (f x + e\right ) + 1\right ) - c \log \left (\cos \left (f x + e\right )^{2} + \sin \left (f x + e\right )^{2} - 2 \, \sin \left (f x + e\right ) + 1\right ) - 4 \, c \sin \left (f x + e\right )\right )} \sqrt{c}}{2 \, \sqrt{a} f} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [B] time = 1.57567, size = 968, normalized size = 9.13 \begin{align*} -\frac{{\left (a f \sqrt{\frac{c^{3}}{a f^{2}}} e^{\left (2 i \, f x + 2 i \, e\right )} \log \left (-\frac{2 \,{\left (c e^{\left (2 i \, f x + 2 i \, e\right )} + c\right )} \sqrt{\frac{a}{e^{\left (2 i \, f x + 2 i \, e\right )} + 1}} \sqrt{\frac{c}{e^{\left (2 i \, f x + 2 i \, e\right )} + 1}} e^{\left (i \, f x + i \, e\right )} -{\left (i \, a f e^{\left (2 i \, f x + 2 i \, e\right )} - i \, a f\right )} \sqrt{\frac{c^{3}}{a f^{2}}}}{2 \,{\left (c e^{\left (2 i \, f x + 2 i \, e\right )} + c\right )}}\right ) - a f \sqrt{\frac{c^{3}}{a f^{2}}} e^{\left (2 i \, f x + 2 i \, e\right )} \log \left (-\frac{2 \,{\left (c e^{\left (2 i \, f x + 2 i \, e\right )} + c\right )} \sqrt{\frac{a}{e^{\left (2 i \, f x + 2 i \, e\right )} + 1}} \sqrt{\frac{c}{e^{\left (2 i \, f x + 2 i \, e\right )} + 1}} e^{\left (i \, f x + i \, e\right )} -{\left (-i \, a f e^{\left (2 i \, f x + 2 i \, e\right )} + i \, a f\right )} \sqrt{\frac{c^{3}}{a f^{2}}}}{2 \,{\left (c e^{\left (2 i \, f x + 2 i \, e\right )} + c\right )}}\right ) -{\left (-4 i \, c e^{\left (3 i \, f x + 3 i \, e\right )} + 4 i \, c e^{\left (2 i \, f x + 2 i \, e\right )} - 4 i \, c e^{\left (i \, f x + i \, e\right )} + 4 i \, c\right )} \sqrt{\frac{a}{e^{\left (2 i \, f x + 2 i \, e\right )} + 1}} \sqrt{\frac{c}{e^{\left (2 i \, f x + 2 i \, e\right )} + 1}} e^{\left (i \, f x + i \, e\right )}\right )} e^{\left (-2 i \, f x - 2 i \, e\right )}}{2 \, a f} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{\left (- c \left (i \tan{\left (e + f x \right )} - 1\right )\right )^{\frac{3}{2}}}{\sqrt{a \left (i \tan{\left (e + f x \right )} + 1\right )}}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{{\left (-i \, c \tan \left (f x + e\right ) + c\right )}^{\frac{3}{2}}}{\sqrt{i \, a \tan \left (f x + e\right ) + a}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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